Split Array Largest Sum

Algorithms
Hard
Microsoft
143K views

Given an array `nums` and an integer $k$, split `nums` into $k$ non-empty contiguous subarrays such that the largest sum among these $k$ subarrays is minimized. Use Binary Search on the answer.

Why Interviewers Ask This

Microsoft asks this to evaluate a candidate's ability to transform an optimization problem into a decision problem, a key skill for distributed systems. It tests if you recognize that minimizing the maximum sum is monotonic, allowing binary search on the answer rather than brute force. This reveals your capacity to handle resource allocation constraints and optimize load balancing scenarios efficiently.

How to Answer This Question

1. Clarify constraints: Confirm array size, element ranges, and k value to determine time complexity needs. 2. Define the search space: Explain that the minimum possible max-sum is the largest single element, and the maximum is the total sum of the array. 3. Validate the monotonic property: Articulate why if a specific max-sum 'X' is feasible, any value greater than 'X' is also feasible, justifying binary search. 4. Design the greedy check function: Describe iterating through the array to count subarrays; if current sum exceeds 'mid', increment count and reset sum. 5. Refine logic: Handle edge cases like k=1 or k=n, then synthesize the solution by narrowing the search range based on the feasibility check until convergence.

Key Points to Cover

  • Recognizing the problem requires Binary Search on the Answer rather than Dynamic Programming
  • Defining the correct search space bounds based on the maximum element and total sum
  • Implementing a linear-time greedy validation function to check feasibility
  • Explaining the monotonic nature of the solution space clearly
  • Achieving optimal time complexity of O(n log(Sum)) instead of O(n^2)

Sample Answer

To solve the Split Array Largest Sum problem, I would first analyze the constraints. Since we need to minimize the largest sum among k subarrays, a brute-force approach checking all partitions would be O(n^k), which is infeasible. Instead, I recognize this as a classic 'minimize the maximum' problem suitable for Binary Search on the Answer. The key insight is that the feasibility function is monotonic: if it is possible to split the array with a maximum sum of X, it is definitely possible with any value larger than X. I would set my binary search range where the lower bound is the maximum element in nums (since no subarray can be smaller than its largest element) and the upper bound is the sum of all elements (representing one single subarray). For each midpoint 'mid', I implement a helper function to check if k subarrays are sufficient. This function greedily accumulates elements; if adding the next element exceeds 'mid', it starts a new subarray. If the required subarrays exceed k, 'mid' is too small. Otherwise, it is feasible, and we try smaller values. This approach achieves O(n log(sum)) time complexity, aligning well with Microsoft's focus on scalable algorithms for large datasets.

Common Mistakes to Avoid

  • Attempting a Dynamic Programming solution which results in O(n*k) or worse complexity without optimizing the state transitions
  • Setting the lower bound of the binary search to 0 instead of the maximum element in the array
  • Failing to handle the edge case where k equals the array length or k equals 1
  • Using a non-greedy approach in the validation step, leading to incorrect feasibility checks

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