Validate Binary Search Tree
Given the root of a binary tree, determine if it is a valid Binary Search Tree (BST). You must check that the full range constraint is respected for all nodes.
Why Interviewers Ask This
Meta evaluates this question to assess a candidate's ability to handle range constraints beyond simple local comparisons. Interviewers look for deep understanding of tree traversal, recursion limits, and the capacity to maintain state across nested calls without relying on global variables.
How to Answer This Question
1. Clarify requirements: Confirm if duplicate values are allowed and define the strict BST property (left < root < right). 2. Identify the pitfall: Explicitly state that comparing only immediate children is insufficient because a node must respect the entire ancestor path. 3. Select strategy: Propose the 'in-order traversal' method where a valid BST yields sorted output, or the 'recursive range validation' approach passing min/max bounds down the tree. 4. Define implementation: Walk through how to initialize bounds as negative/positive infinity and update them at each step. 5. Analyze complexity: Discuss O(n) time and O(h) space complexity, noting stack depth considerations for skewed trees typical in Meta's large-scale systems.
Key Points to Cover
- Explicitly acknowledging that local comparisons are insufficient for global validity
- Demonstrating knowledge of in-order traversal properties for sorted sequences
- Correctly implementing min/max bound propagation in recursive calls
- Handling edge cases like integer overflow or null nodes gracefully
- Analyzing time and space complexity relative to tree height
Sample Answer
To validate a Binary Search Tree, I first clarify that every node's value must strictly fall within a specific range defined by its ancestors, not just its immediate parent. A common trap is checking only if left_child < current < right_child, which fails for nodes deeper in the tree that violate the global constraint. For example, a right child of a left subtree might be larger than the root but smaller than its own parent, breaking the BST property globally.
I recommend two robust approaches. First, an in-order traversal: since a valid BST produces a strictly increasing sequence when traversed in-order, we can track the previous visited node and ensure the current node is strictly greater. If any node violates this order, the tree is invalid. Alternatively, and perhaps more intuitively for maintaining context, I use recursive range validation. We pass down minimum and maximum allowable values starting with negative and positive infinity. As we traverse left, we update the upper bound to the current node's value; as we traverse right, we update the lower bound. This ensures every node respects the full ancestral path. Both methods run in O(n) time and O(h) space, where h is the tree height. Given Meta's focus on scalable data structures, ensuring the solution handles skewed trees efficiently via tail recursion optimization or iterative stacks would be a strong addition during implementation.
Common Mistakes to Avoid
- Comparing only immediate children instead of enforcing ancestor range constraints
- Using global variables to store the previous node, which breaks re-entrancy
- Failing to handle duplicate values correctly based on problem definition
- Ignoring stack overflow risks in highly unbalanced or skewed tree scenarios
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